C++/Algorithems

## Finding closest pair of points in two disjoint sets of points

The finding nearest pair of points in two disjoint sets of points (or Polygons made of points) can be found in O(nlogn) computational complexity (with O(n) memory complexity). With ordinary tree or graph search, solving this is not possible because we do not know the starting and ending points in advance. The k-d binary search tree can used to solve…

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DWH

## SSAS : Save hours by automating the cube deployments!

Every now and then it is quite an overhead in large development environments to deploy the SSAS cubes at a large scale. Automating this process particularly helps when doing lots of changes in the SSDT (SQL Server data tools) in the development environment and when finished the changes then deploying the cubes in the UAT environment. Then after completion of…

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DWH

## Junk Dimensions?!

Quite often SSAS/DWH designers face with the situation with several if not dozens of small what could be called small dimensions, e.g. Yes/No flags, status etc. To make each of them a separate dimension (say 20 different Yes/No flags dimensions) would simply clutter the data mart and eventually the SSAS cube. The convenient way in my opinion is to rather…

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C++/Algorithems

## Minimum sliding Window Problem can be solved in O(n) rather easily

Several solutions to the minumum sliding window Problem actually create complexity but in my opinion it can solved with rather ease while still maintaining the time and Memory complexity at O(n). The idea is to basically create a temporary sum and Keep adding the new elements and subtracting the old elements as we scan the Array while keeping record of…

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C++/Algorithems

## Addition without using any arthmetic operator

Often is this puzzle brought up to test someone’s ‘bits’ knowledge but it is rather straight forward to add two numbers (whole numbers). It works by same principle as we do it by Hand, i.e. add two numbers, Keep the carry and add it into the sum. In programming we can do it achieve the simple ‘addition’ via XOR operator i.e. ^…

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